y^2-(2*y)+(2)=0

Solution for y^2-(2*y)+(2)=0 equation:

Simplifying
y2 + -1(2y) + (2) = 0

Remove parenthesis around (2y)
y2 + -1 * 2y + (2) = 0

Multiply -1 * 2
y2 + -2y + (2) = 0
y2 + -2y + 2 = 0

Reorder the terms:
2 + -2y + y2 = 0

Solving
2 + -2y + y2 = 0

Solving for variable 'y'.

Begin completing the square.

Move the constant term to the right:

Add '-2' to each side of the equation.
2 + -2y + -2 + y2 = 0 + -2

Reorder the terms:
2 + -2 + -2y + y2 = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -2y + y2 = 0 + -2
-2y + y2 = 0 + -2

Combine like terms: 0 + -2 = -2
-2y + y2 = -2

The y term is -2y.  Take half its coefficient (-1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
-2y + 1 + y2 = -2 + 1

Reorder the terms:
1 + -2y + y2 = -2 + 1

Combine like terms: -2 + 1 = -1
1 + -2y + y2 = -1

Factor a perfect square on the left side:
(y + -1)(y + -1) = -1

Can't calculate square root of the right side.

The solution to this equation could not be determined.